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It a leakage current of 5 uA at 1 volt. Even it a leakage current, I need to increase current source to until I get get a V voltage drop over Zener diode. over is V over resistor.
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forward powerloss is Vd * Id Vd is forward volt drop and Id is forward current). reverse powerloss (due to leakage) is Vrr * Irr Vrr is reverse blocking voltage and Irr is reverse flowing current). Equation 9 in paper states: P l e a k = (1 + δ) ⋅ I r r ⋅ V r r.
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